1. **State the problem:** We need to find the distance the bus travels between Hawkes Meadow and Brunswick Street. 2. **Identify the given information:** - Average speed of the bus: $29$ km/h - Time at Hawkes Meadow: 14:25 - Time at Brunswick Street: 14:40 3. **Calculate the time taken between the two stops:** - Time difference = 14:40 - 14:25 = 15 minutes - Convert minutes to hours: $\frac{15}{60} = 0.25$ hours 4. **Use the formula for distance:** $$\text{Distance} = \text{Speed} \times \text{Time}$$ 5. **Substitute the values:** $$\text{Distance} = 29 \times 0.25$$ 6. **Calculate the distance:** $$\text{Distance} = 7.25 \text{ km}$$ 7. **Round to 1 decimal place:** $$7.25 \approx 7.3 \text{ km}$$ **Final answer:** The bus travels **7.3 km** between Hawkes Meadow and Brunswick Street.