1. **State the problem:** Isabelle pays 2.50 each time she rides the bus, or she can buy a bus pass for 15 plus 1.00 per ride. We want to find after how many rides the total cost is the same for both options. 2. **Set up the equation:** Let $x$ be the number of bus rides. Cost without pass: $2.50x$ Cost with pass: $15 + 1.00x$ We want to find $x$ such that: $$2.50x = 15 + 1.00x$$ 3. **Solve the equation:** Subtract $1.00x$ from both sides: $$2.50x - \cancel{1.00x} = 15 + \cancel{1.00x}$$ $$1.50x = 15$$ 4. **Divide both sides by 1.50:** $$x = \frac{15}{1.50}$$ 5. **Simplify the fraction:** $$x = 10$$ 6. **Interpretation:** After 10 bus rides, the cost of both options is the same. **Final answer:** $10$ rides