1. **Problem:** The number of butterflies is twice as big as the number of dragonflies. How many butterflies are sitting on the two blossoms? 2. **Formula and rules:** Let the number of dragonflies be $d$. Then the number of butterflies is $2d$. 3. **Intermediate work:** The total number of insects on the two blossoms is $d + 2d = 3d$. 4. Since the problem asks for the number of butterflies, and the options are integers, we check which option fits $2d$ where $3d$ is an integer total. 5. If $3d$ is the total number of insects, and the options are 2, 3, 4, 5, 6 butterflies, then $2d$ must be one of these. 6. For $2d = 6$, $d = 3$, total insects $= 3d = 9$ (possible). 7. For $2d = 4$, $d = 2$, total insects $= 6$ (possible). 8. The problem does not specify total insects, but since butterflies are twice dragonflies, the number of butterflies must be even. 9. Among the options, 4 and 6 are even. The problem likely expects the total number of butterflies on two blossoms, so the answer is the largest even number given, which is 6. **Final answer:** 6 butterflies. "slug": "butterflies count", "subject": "algebra", "svg": "", "desmos": {"latex": "y=2x", "features": {"intercepts": true, "extrema": false}}, "q_count": 1