1. **State the problem:** Calculate the value of $$C = 2 \sqrt{\frac{81}{16} - \frac{5}{3} \left(\frac{1}{4} - \frac{1}{6} \times 0.3 \right)^2 + \left( \frac{5}{8} + 1 \times \left(1 - \frac{1}{5} \right) \right)^2}$$.
2. **Simplify inside the parentheses:**
- Calculate $$\frac{1}{6} \times 0.3 = 0.05$$.
- Then $$\frac{1}{4} - 0.05 = 0.25 - 0.05 = 0.2$$.
3. **Square the result:**
$$0.2^2 = 0.04$$.
4. **Calculate the second bracket:**
- Calculate $$1 - \frac{1}{5} = 1 - 0.2 = 0.8$$.
- Multiply by 1: $$1 \times 0.8 = 0.8$$.
- Add $$\frac{5}{8} = 0.625$$.
- So, $$0.625 + 0.8 = 1.425$$.
5. **Square the sum:**
$$1.425^2 = 2.030625$$.
6. **Substitute back into the expression under the square root:**
$$\frac{81}{16} = 5.0625$$.
7. **Calculate the term with the squared difference:**
$$\frac{5}{3} \times 0.04 = \frac{5}{3} \times 0.04 = 0.066666...$$.
8. **Put all together under the square root:**
$$5.0625 - 0.066666... + 2.030625 = 5.0625 - 0.066666... + 2.030625 = 7.026458...$$.
9. **Calculate the square root:**
$$\sqrt{7.026458...} \approx 2.6508$$.
10. **Multiply by 2:**
$$C = 2 \times 2.6508 = 5.3016$$.
**Final answer:** $$C \approx 5.3016$$.
Calculate C 34181B
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