1. **Problem (a):** Tom's car has lost 18% of its value and is now worth 18450.
2. **Formula:** If the original value is $V$, then after losing 18%, the value is $V \times (1 - 0.18) = V \times 0.82$.
3. **Set up equation:**
$$18450 = V \times 0.82$$
4. **Solve for $V$:**
$$V = \frac{18450}{0.82}$$
5. **Intermediate step with cancellation:**
$$V = \frac{18450}{\cancel{0.82}} \times \frac{\cancel{1}}{1}$$
6. **Calculate:**
$$V = 22500$$
7. **Answer (a):** The car was originally worth 22500.
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1. **Problem (b):** Solve the inequality $7 - 4x \geq 2x - 5$ where $x \in \mathbb{Z}$.
2. **Rearrange terms:**
$$7 - 4x \geq 2x - 5$$
3. **Bring all $x$ terms to one side and constants to the other:**
$$7 + 5 \geq 2x + 4x$$
4. **Simplify:**
$$12 \geq 6x$$
5. **Divide both sides by 6:**
$$\frac{12}{6} \geq \frac{6x}{6}$$
6. **Intermediate step with cancellation:**
$$\frac{\cancel{12}}{\cancel{6}} \geq \cancel{\frac{6x}{6}}$$
7. **Simplify:**
$$2 \geq x$$
8. **Rewrite inequality:**
$$x \leq 2$$
9. **Answer (b):** The solution set is all integers $x$ such that $x \leq 2$.
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1. **Problem (c):** Solve the simultaneous equations:
$$x^2 + y^2 = 41$$
$$2x - y = 3$$
2. **Express $y$ from second equation:**
$$y = 2x - 3$$
3. **Substitute into first equation:**
$$x^2 + (2x - 3)^2 = 41$$
4. **Expand:**
$$x^2 + (4x^2 - 12x + 9) = 41$$
5. **Combine like terms:**
$$5x^2 - 12x + 9 = 41$$
6. **Bring all terms to one side:**
$$5x^2 - 12x + 9 - 41 = 0$$
7. **Simplify:**
$$5x^2 - 12x - 32 = 0$$
8. **Use quadratic formula:**
$$x = \frac{12 \pm \sqrt{(-12)^2 - 4 \times 5 \times (-32)}}{2 \times 5}$$
9. **Calculate discriminant:**
$$144 + 640 = 784$$
10. **Square root:**
$$\sqrt{784} = 28$$
11. **Calculate roots:**
$$x = \frac{12 \pm 28}{10}$$
12. **First root:**
$$x = \frac{12 + 28}{10} = \frac{40}{10} = 4$$
13. **Second root:**
$$x = \frac{12 - 28}{10} = \frac{-16}{10} = -\frac{8}{5}$$
14. **Since $x \in \mathbb{Z}$, discard $-\frac{8}{5}$ and keep $x=4$ only.**
15. **Find $y$ for $x=4$:**
$$y = 2(4) - 3 = 8 - 3 = 5$$
16. **Answer (c):** The integer solution is $(x,y) = (4,5)$.
Car Value Inequality C2Bb2D
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