Subjects algebra

Celsius Fahrenheit 0218D3

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1. **State the problem:** Solve for the temperature in Fahrenheit ($F$) given the Celsius temperature is 40 using the formula relating Celsius and Fahrenheit. 2. **Formula:** The conversion formula is $$C = \frac{5}{9}(F - 32)$$ where $C$ is Celsius and $F$ is Fahrenheit. 3. **Substitute the given value:** Here, $C = 40$, so $$40 = \frac{5}{9}(F - 32)$$ 4. **Isolate $F - 32$:** Multiply both sides by 9 to cancel the denominator: $$40 \times 9 = 5(F - 32)$$ $$360 = 5(F - 32)$$ 5. **Divide both sides by 5:** $$\cancel{5} \times 72 = \cancel{5}(F - 32)$$ $$72 = F - 32$$ 6. **Solve for $F$:** Add 32 to both sides: $$72 + 32 = F$$ $$104 = F$$ **Final answer:** The temperature in Fahrenheit is $\boxed{104}$ degrees.