1. **State the problem:** Check if the points (1, 2) and (4, 0) are solutions of the equation $x - 2y = 4$. 2. **Recall the rule:** A point $(x, y)$ is a solution to the equation if, when substituted into the equation, the left side equals the right side. 3. **Check point (1, 2):** Substitute $x=1$ and $y=2$ into the equation: $$1 - 2 \times 2 = 1 - 4 = -3$$ The right side is 4, but the left side is $-3$, so (1, 2) is **not** a solution. 4. **Check point (4, 0):** Substitute $x=4$ and $y=0$ into the equation: $$4 - 2 \times 0 = 4 - 0 = 4$$ The left side equals the right side, so (4, 0) **is** a solution. **Final answer:** (1, 2) is not a solution; (4, 0) is a solution of the equation $x - 2y = 4$.