1. **State the problem:** We start with equal masses of chemical A and chemical B. Chemical A's mass increases by 2600%, and chemical B's mass increases by 380%. We want to find how many times greater the mass of chemical A is compared to chemical B at the end. 2. **Understand percentage increase:** A 2600% increase means the final mass is the original mass plus 2600% of it, which is $1 + \frac{2600}{100} = 27$ times the original mass. Similarly, a 380% increase means the final mass is $1 + \frac{380}{100} = 4.8$ times the original mass. 3. **Set variables:** Let the original mass of each chemical be $m$. 4. **Calculate final masses:** - Final mass of A: $27m$ - Final mass of B: $4.8m$ 5. **Find the ratio:** $$\text{Ratio} = \frac{27m}{4.8m} = \frac{27}{4.8} = 5.625$$ 6. **Interpretation:** The mass of chemical A is approximately 5.63 times greater than the mass of chemical B. **Answer: D. 5.63**