1. **State the problem:** There were five times as many children as adults at the picnic. If at least 120 people attended, find how many adults and children were at the picnic. 2. **Define variables:** Let $a$ be the number of adults and $c$ be the number of children. 3. **Write the relationships:** We know $c = 5a$ because there are five times as many children as adults. 4. **Write the inequality for total attendance:** The total number of people is at least 120, so $$a + c \geq 120$$ 5. **Substitute $c$ in the inequality:** $$a + 5a \geq 120$$ 6. **Simplify:** $$6a \geq 120$$ 7. **Solve for $a$:** $$a \geq \frac{120}{6}$$ $$a \geq 20$$ 8. **Find $c$ using $c=5a$:** $$c = 5 \times 20 = 100$$ 9. **Interpretation:** The minimum number of adults is 20, and the corresponding number of children is 100, making the total 120 people. **Final answer:** There are at least 20 adults and 100 children at the picnic.