Subjects algebra

Chocolate Share A6F68B

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1. **State the problem:** Emman had $\frac{3}{4}$ of a box of chocolates. He gave $\frac{2}{3}$ of his chocolates to Lizette. Then Lizette gave $\frac{1}{2}$ of her chocolates to Anne. We need to find what part of the box Anne has. 2. **Find how much Lizette received from Emman:** $$\text{Lizette's share} = \frac{2}{3} \times \frac{3}{4}$$ 3. **Simplify the multiplication:** $$\frac{2}{3} \times \frac{3}{4} = \frac{\cancel{2}^2}{\cancel{3}^1} \times \frac{\cancel{3}^1}{4} = \frac{2}{4} = \frac{1}{2}$$ Lizette received $\frac{1}{2}$ of the box. 4. **Find how much Anne received from Lizette:** $$\text{Anne's share} = \frac{1}{2} \times \frac{1}{2} = \frac{1}{4}$$ 5. **Final answer:** Anne has $\frac{1}{4}$ of the box of chocolates. This means Anne has one quarter of the entire box.