1. **State the problem:** Find the center and radius of the circle given by the equation $$(x + 3)^2 + (y - 5)^2 = 16$$. 2. **Recall the standard form of a circle's equation:** $$ (x - h)^2 + (y - k)^2 = r^2 $$ where $(h, k)$ is the center and $r$ is the radius. 3. **Identify the center:** Compare $$(x + 3)^2 + (y - 5)^2 = 16$$ with the standard form. Note that $x + 3$ can be written as $x - (-3)$, so $h = -3$. Similarly, $y - 5$ means $k = 5$. Therefore, the center is $$(-3, 5)$$. 4. **Find the radius:** The right side of the equation is $16$, which equals $r^2$. So, $$r = \sqrt{16} = 4$$. 5. **Final answer:** Center: $$(-3, 5)$$ Radius: $$4$$