1. **Stating the problem:** In a class, there are girls and 30 boys. 28 boys pass, all girls pass. The total passing students are 95% of the class. Find the number of girls and boys in the class. 2. **Formula and rules:** Let the number of girls be $g$. Total students = $g + 30$. Passing students = girls (all pass) + 28 boys = $g + 28$. Given passing students are 95% of total students: $$g + 28 = 0.95(g + 30)$$ 3. **Solving the equation:** $$g + 28 = 0.95g + 28.5$$ Subtract $0.95g$ from both sides: $$g - 0.95g + 28 = 28.5$$ $$0.05g + 28 = 28.5$$ Subtract 28 from both sides: $$0.05g = 0.5$$ Divide both sides by 0.05: $$g = \frac{0.5}{0.05}$$ $$g = \cancel{\frac{0.5}{0.05}} = 10$$ 4. **Answer:** There are 10 girls and 30 boys in the class. 5. **Verification:** Total students = $10 + 30 = 40$. Passing students = $10 + 28 = 38$. Percentage passing = $\frac{38}{40} \times 100 = 95\%$ which matches the problem statement.