1. **State the problem:** We have two linear functions, Function A given by the equation $y=4x-2$ and Function B given by a table of points: $(-4,-9)$, $(-3,-7)$, and $(8,15)$. We need to compare their y-intercepts and determine which statement is true. 2. **Recall the y-intercept definition:** The y-intercept of a linear function is the value of $y$ when $x=0$. For Function A, the y-intercept is directly given by the constant term in the equation. 3. **Find the y-intercept of Function A:** From $y=4x-2$, when $x=0$, $y=-2$. So, the y-intercept of Function A is $-2$. 4. **Find the slope of Function B:** Using two points from the table, say $(-4,-9)$ and $(-3,-7)$, the slope $m$ is $$m=\frac{y_2 - y_1}{x_2 - x_1} = \frac{-7 - (-9)}{-3 - (-4)} = \frac{2}{1} = 2.$$ 5. **Find the y-intercept of Function B:** Use the slope-intercept form $y=mx+b$ and one point to solve for $b$. Using point $(-4,-9)$: $$-9 = 2(-4) + b$$ $$-9 = -8 + b$$ $$b = -9 + 8 = -1$$ So, the y-intercept of Function B is $-1$. 6. **Compare the y-intercepts:** Function A has y-intercept $-2$, Function B has y-intercept $-1$. Since $-2 < -1$, the y-intercept of Function A is less than the y-intercept of Function B. **Final answer:** The y-intercept of Function A is less than the y-intercept of Function B.