1. Stating the problem: We need to complete the missing values in the ratio table where each pair forms equivalent ratios. 2. First, identify ratio pairs given: - Row 1: $\frac{3}{1}$ - Row 4: $\frac{66}{22}$ - Row 5: $\frac{96}{32}$ - Row 3 right side: 5 - Row 2 left side: 6 3. Simplify known ratios: - $\frac{3}{1} = 3$ - $\frac{66}{22} = 3$ - $\frac{96}{32} = \frac{96 \div 32}{32 \div 32} = \frac{3}{1} = 3$ All these simplify to 3, so the ratio constant is 3. 4. Find missing value in Row 2 right (ratio with left 6): - Since ratio = 3, $\frac{6}{x} = 3$ so $x = \frac{6}{3} = 2$ 5. Find missing value in Row 3 left (ratio with right 5): - Since ratio = 3, $\frac{x}{5} = 3$ so $x = 3 \times 5 = 15$ 6. Completed table is: | Left | Right | |-------|-------| | 3 | 1 | | 6 | 2 | | 15 | 5 | | 66 | 22 | | 96 | 32 | Final answer: Missing numbers are 2 (Row 2 right) and 15 (Row 3 left).