1. **Problem Statement:** Complete the table for the function $y = x^2 - 2x + 2$ at given $x$ values. 2. **Formula:** Use the function $y = x^2 - 2x + 2$ to calculate $y$ for each $x$. 3. **Calculations:** - For $x = -2$: $$y = (-2)^2 - 2(-2) + 2 = 4 + 4 + 2 = 10$$ - For $x = -1$: $$y = (-1)^2 - 2(-1) + 2 = 1 + 2 + 2 = 5$$ - For $x = 0$: $$y = 0^2 - 2(0) + 2 = 0 + 0 + 2 = 2$$ - For $x = 1$: $$y = 1^2 - 2(1) + 2 = 1 - 2 + 2 = 1$$ - For $x = 2$: $$y = 2^2 - 2(2) + 2 = 4 - 4 + 2 = 2$$ - For $x = 3$: $$y = 3^2 - 2(3) + 2 = 9 - 6 + 2 = 5$$ - For $x = 4$: $$y = 4^2 - 2(4) + 2 = 16 - 8 + 2 = 10$$ 4. **Completed Table:** | x | -2 | -1 | 0 | 1 | 2 | 3 | 4 | |----|----|----|---|---|---|---|---| | y | 10 | 5 | 2 | 1 | 2 | 5 | 10| Final answer: The completed table values for $y$ are 10, 5, 2, 1, 2, 5, 10 respectively for $x = -2, -1, 0, 1, 2, 3, 4$.