Subjects algebra

Complex Multiplication 1D4595

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1. **State the problem:** Multiply the complex numbers $(5 - 4i)$ and $(6 - 3i)$ and write the answer in standard form $a + bi$. 2. **Recall the formula:** To multiply two complex numbers $(a + bi)(c + di)$, use the distributive property: $$ (a + bi)(c + di) = ac + adi + bci + bdi^2 $$ Remember that $i^2 = -1$. 3. **Apply the formula:** $$ (5 - 4i)(6 - 3i) = 5 \times 6 + 5 \times (-3i) + (-4i) \times 6 + (-4i) \times (-3i) $$ 4. **Calculate each term:** $$ = 30 - 15i - 24i + 12i^2 $$ 5. **Simplify $i^2$ term:** Since $i^2 = -1$, $$ 12i^2 = 12 \times (-1) = -12 $$ 6. **Combine like terms:** $$ 30 - 15i - 24i - 12 = (30 - 12) + (-15i - 24i) = 18 - 39i $$ 7. **Final answer:** The product in standard form is $$ \boxed{18 - 39i} $$