Question: For $f(x) = 7x + 8$ and $g(x) = 4x$, find the following composite functions and state the domain of each.
(a) $f \circ g$ (b) $g \circ f$ (c) $f \circ f$ (d) $g \circ g$
1. **State the problem:**
We are given two functions:
$$f(x) = 7x + 8$$
$$g(x) = 4x$$
We need to find the composite functions:
(a) $f \circ g$ (which means $f(g(x))$)
(b) $g \circ f$ (which means $g(f(x))$)
(c) $f \circ f$ (which means $f(f(x))$)
(d) $g \circ g$ (which means $g(g(x))$)
and state the domain of each.
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2. **Recall the rule for composite functions:**
The composite function $f \circ g$ is defined as $f(g(x))$, which means you substitute $g(x)$ into $f$.
Since both $f$ and $g$ are linear functions defined for all real numbers, their domains are all real numbers.
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3. **Calculate each composite function:**
(a) $f \circ g = f(g(x)) = f(4x)$
$$f(4x) = 7(4x) + 8 = 28x + 8$$
Domain: Since $g(x)$ is defined for all real $x$ and $f$ is defined for all real inputs, the domain of $f \circ g$ is all real numbers.
(b) $g \circ f = g(f(x)) = g(7x + 8)$
$$g(7x + 8) = 4(7x + 8) = 28x + 32$$
Domain: Both $f$ and $g$ are defined for all real numbers, so domain is all real numbers.
(c) $f \circ f = f(f(x)) = f(7x + 8)$
$$f(7x + 8) = 7(7x + 8) + 8 = 49x + 56 + 8 = 49x + 64$$
Domain: All real numbers.
(d) $g \circ g = g(g(x)) = g(4x)$
$$g(4x) = 4(4x) = 16x$$
Domain: All real numbers.
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4. **Summary:**
- $f \circ g(x) = 28x + 8$, domain: all real numbers
- $g \circ f(x) = 28x + 32$, domain: all real numbers
- $f \circ f(x) = 49x + 64$, domain: all real numbers
- $g \circ g(x) = 16x$, domain: all real numbers
Each composite function is a linear function defined for all real numbers.