1. **State the problem:** We need to find the value of the composition of functions $ (p \circ q)(-2) $, where $ p(x) = 6x $ and $ q(x) = x + 4 $. 2. **Recall the definition of composition:** The composition $ (p \circ q)(x) $ means $ p(q(x)) $. We first apply $ q $ to $ x $, then apply $ p $ to the result. 3. **Calculate $ q(-2) $:** $$ q(-2) = -2 + 4 = 2 $$ 4. **Calculate $ p(q(-2)) = p(2) $:** $$ p(2) = 6 \times 2 = 12 $$ 5. **Final answer:** $$ (p \circ q)(-2) = 12 $$ This means when you plug $-2$ into $ q $, then plug that result into $ p $, you get $ 12 $.