Subjects algebra

Composition Odd 2F07C6

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1. **State the problem:** We are given two odd functions $f$ and $g$ with values at positive $x$ given in a table. We need to find the value of the composition $(f \circ g)(-1)$, which means $f(g(-1))$. 2. **Recall properties of odd functions:** For an odd function $h$, we have $h(-x) = -h(x)$ for all $x$. This allows us to find values at negative inputs using positive inputs. 3. **Find $g(-1)$:** Since $g$ is odd, $$g(-1) = -g(1).$$ From the table, $g(1) = 3$, so $$g(-1) = -3.$$ 4. **Find $f(g(-1)) = f(-3)$:** Since $f$ is odd, $$f(-3) = -f(3).$$ From the table, $f(3) = -4$, so $$f(-3) = -(-4) = 4.$$ 5. **Final answer:** $$(f \circ g)(-1) = f(g(-1)) = 4.$$