1. The problem states that $(f \circ g)(0) = 2$, which means $f(g(0)) = 2$. 2. From the graph, observe the function $g(x)$, which is a downward-opening parabola intersecting the y-axis at 2. This means $g(0) = 2$. 3. Substitute $g(0) = 2$ into the composition: $f(g(0)) = f(2)$. 4. We know $(f \circ g)(0) = 2$, so $f(2) = 2$. 5. From the graph, $f(x)$ is a line passing through the origin with positive slope. Since $f(2) = 2$, the slope $m$ satisfies $2 = m \times 2$, so $m = 1$. 6. Therefore, $f(x) = x$ and $g(0) = 2$. 7. The solution confirms that $(f \circ g)(0) = f(g(0)) = f(2) = 2$ is consistent with the given functions. Final answer: $(f \circ g)(0) = 2$ is true with $f(x) = x$ and $g(0) = 2$.