Subjects algebra

Compound Growth F085F6

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1. The problem asks to solve the expression $$P(1 + \frac{R}{100})^T$$ which represents the amount after $T$ years with an initial principal $P$ and an annual growth rate $R$ percent. 2. This formula is used in compound interest and population growth calculations where the quantity grows by a rate $R$ percent each year. 3. The formula is: $$A = P\left(1 + \frac{R}{100}\right)^T$$ where: - $A$ is the amount after $T$ years, - $P$ is the initial amount, - $R$ is the rate of growth per year (in percent), - $T$ is the number of years. 4. To solve for $A$, substitute the known values of $P$, $R$, and $T$ into the formula and calculate step-by-step. 5. For example, if $P=1000$, $R=5$, and $T=3$, then: $$A = 1000\left(1 + \frac{5}{100}\right)^3 = 1000\left(1 + 0.05\right)^3 = 1000 \times 1.05^3$$ 6. Calculate $1.05^3$: $$1.05^3 = 1.157625$$ 7. Multiply by $P$: $$A = 1000 \times 1.157625 = 1157.625$$ 8. So, the amount after 3 years is $1157.625$. This method applies to any values of $P$, $R$, and $T$.