1. **Stating the problem:** Solve the compound inequality $2 - 2m > 16$ or $9 + 8m \geq 73$. 2. **Solve the first inequality:** \[2 - 2m > 16\] Subtract 2 from both sides: \[2 - 2m - 2 > 16 - 2\] \[-2m > 14\] Divide both sides by $-2$, remembering to reverse the inequality sign because we divide by a negative number: \[m < \cancel{-2} \frac{14}{\cancel{-2}}\Rightarrow m < -7\] 3. **Solve the second inequality:** \[9 + 8m \geq 73\] Subtract 9 from both sides: \[8m \geq 73 - 9\] \[8m \geq 64\] Divide both sides by 8: \[m \geq \cancel{8} \frac{64}{\cancel{8}}\Rightarrow m \geq 8\] 4. **Combine the solutions:** The solution is $m < -7$ or $m \geq 8$. This means $m$ is either less than $-7$ or greater than or equal to $8$. **Final answer:** $$m < -7 \text{ or } m \geq 8$$