1. Problem: Find the original cost of a computer that costs 14760 after 3 years, depreciating at 5% per annum. 2. Formula: The depreciation formula is $$V = P(1 - r)^t$$ where $V$ is the value after $t$ years, $P$ is the original price, $r$ is the depreciation rate, and $t$ is time in years. 3. Substitute known values: $$14760 = P(1 - 0.05)^3$$ 4. Simplify the depreciation factor: $$14760 = P(0.95)^3 = P(0.857375)$$ 5. Solve for $P$: $$P = \frac{14760}{0.857375}$$ 6. Show cancellation: $$P = \frac{14760}{\cancel{0.857375}} \times \cancel{1}$$ 7. Calculate $P$: $$P \approx 17220.68$$ Answer: The original cost of the computer was approximately 17220.68.