1. **State the problem:** The sum of two consecutive integers is -13. If 2 is added to the smaller integer and 3 is subtracted from the larger integer, find the product of the two resulting integers.
2. **Define variables:** Let the smaller integer be $x$. Then the next consecutive integer is $x+1$.
3. **Write the equation for the sum:**
$$x + (x+1) = -13$$
4. **Simplify the equation:**
$$2x + 1 = -13$$
5. **Solve for $x$:**
$$2x = -13 - 1$$
$$2x = -14$$
$$x = \frac{-14}{2}$$
$$x = -7$$
6. **Find the two integers:**
Smaller integer: $x = -7$
Larger integer: $x+1 = -6$
7. **Modify the integers as per the problem:**
Smaller integer plus 2: $-7 + 2 = -5$
Larger integer minus 3: $-6 - 3 = -9$
8. **Find the product of the resulting integers:**
$$(-5) \times (-9) = 45$$
**Final answer:** 45
Consecutive Integers A4Ef1A
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