1. The problem asks for the constant rate of change between time and calories burned from the given table. 2. The rate of change formula is \[ \text{rate of change} = \frac{\text{change in calories}}{\text{change in time}} = \frac{\Delta y}{\Delta x} \] 3. From the table, choose two points, for example (15, 60) and (30, 120). 4. Calculate the change in calories: \[ 120 - 60 = 60 \] 5. Calculate the change in time: \[ 30 - 15 = 15 \] 6. Compute the rate of change: \[ \frac{60}{15} = 4 \] 7. This means the calories increase by 4 calories per minute. 8. Check other intervals to confirm the rate is constant: - Between (30, 120) and (45, 180): \[ \frac{180 - 120}{45 - 30} = \frac{60}{15} = 4 \] - Between (45, 180) and (60, 240): \[ \frac{240 - 180}{60 - 45} = \frac{60}{15} = 4 \] 9. Since the rate of change is constant and equals 4, the answer is option d: 4 calories per minute.