Subjects algebra

Contractor Costs 131Afc

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1. **Problem Statement:** Mrs. Hanim wants to find the equations for the total cost $y$ based on the number of hours $x$ for two contractors, A and B. 2. **Contractor A:** From the graph, the points are approximately $(1, 200)$ and $(3, 400)$. 3. **Find the slope $m$ for Contractor A:** $$m = \frac{400 - 200}{3 - 1} = \frac{200}{2} = 100$$ 4. **Use point-slope form to find the equation:** Using point $(1, 200)$: $$y - 200 = 100(x - 1)$$ $$y = 100x - 100 + 200$$ $$y = 100x + 100$$ 5. **Contractor B:** From Table 1, points are $(1, 295)$ and $(2, 340)$. 6. **Find the slope $m$ for Contractor B:** $$m = \frac{340 - 295}{2 - 1} = \frac{45}{1} = 45$$ 7. **Use point-slope form for Contractor B:** Using point $(1, 295)$: $$y - 295 = 45(x - 1)$$ $$y = 45x - 45 + 295$$ $$y = 45x + 250$$ **Final equations:** - Contractor A: $$y = 100x + 100$$ - Contractor B: $$y = 45x + 250$$