Subjects algebra

Coordinate Operations 087Fbf

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1. **State the problem:** We need to evaluate the expression involving coordinate pairs: $$(6027,-343) \div (625,-649) \times (625,-649) \times (6204,-343) \times (6027,-649)$$ 2. **Understand the operations:** Division and multiplication of coordinate pairs are not standard operations. We interpret division and multiplication component-wise: For two points $A=(x_1,y_1)$ and $B=(x_2,y_2)$: - Multiplication: $A \times B = (x_1 \times x_2, y_1 \times y_2)$ - Division: $A \div B = \left(\frac{x_1}{x_2}, \frac{y_1}{y_2}\right)$ 3. **Apply division first:** $$ (6027,-343) \div (625,-649) = \left(\frac{6027}{625}, \frac{-343}{-649}\right) $$ Simplify the fractions: $$ \frac{6027}{625} \approx 9.6432, \quad \frac{-343}{-649} = \frac{343}{649} \approx 0.5285 $$ 4. **Multiply the result by the next point $(625,-649)$:** $$ \left(9.6432, 0.5285\right) \times (625,-649) = (9.6432 \times 625, 0.5285 \times -649) $$ Calculate: $$ 9.6432 \times 625 = 6027, \quad 0.5285 \times -649 = -343 $$ So the product is $(6027, -343)$. 5. **Multiply by the next point $(6204,-343)$:** $$ (6027, -343) \times (6204, -343) = (6027 \times 6204, -343 \times -343) $$ Calculate: $$ 6027 \times 6204 = 37365708, \quad (-343) \times (-343) = 117649 $$ So the product is $(37365708, 117649)$. 6. **Multiply by the last point $(6027,-649)$:** $$ (37365708, 117649) \times (6027, -649) = (37365708 \times 6027, 117649 \times -649) $$ Calculate: $$ 37365708 \times 6027 = 225204927516, \quad 117649 \times -649 = -76353501 $$ So the final result is: $$ \boxed{(225204927516, -76353501)} $$