Subjects algebra

Cordial Water Ratio B13E81

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1. **State the problem:** We have 1 litre of fruit drink made by mixing cordial and water in the ratio 1:7. 2. **Initial quantities:** Since the total is 1 litre and the ratio is 1:7, the cordial amount is \( \frac{1}{1+7} = \frac{1}{8} \) litres and water amount is \( \frac{7}{8} \) litres. 3. **Goal:** Add some water \( x \) litres to make the new ratio of cordial to water 3:25. 4. **Set up the equation:** After adding water, cordial remains \( \frac{1}{8} \) litres, water becomes \( \frac{7}{8} + x \). The ratio is \( \frac{\text{cordial}}{\text{water}} = \frac{3}{25} \), so: $$ \frac{\frac{1}{8}}{\frac{7}{8} + x} = \frac{3}{25} $$ 5. **Solve for \( x \):** Multiply both sides by \( \frac{7}{8} + x \): $$ \frac{1}{8} = \frac{3}{25} \left( \frac{7}{8} + x \right) $$ Multiply both sides by 25: $$ 25 \times \frac{1}{8} = 3 \left( \frac{7}{8} + x \right) $$ Simplify left side: $$ \frac{25}{8} = 3 \left( \frac{7}{8} + x \right) $$ Divide both sides by 3: $$ \frac{25}{8} \times \frac{1}{3} = \frac{7}{8} + x $$ $$ \frac{25}{24} = \frac{7}{8} + x $$ Subtract \( \frac{7}{8} \) from both sides: $$ x = \frac{25}{24} - \frac{7}{8} $$ Find common denominator 24: $$ x = \frac{25}{24} - \frac{21}{24} = \frac{4}{24} = \frac{1}{6} $$ 6. **Answer:** The amount of water to add is \( \frac{1}{6} \) litres. **Final answer:** \( \boxed{\frac{1}{6} \text{ litres}} \)