Subjects algebra

Cost Comparison B4Fec9

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1. **State the problem:** Two friends, Hana and Freya, have different bills for printing photographs. Hana pays 16.50 for 150 photos, and Freya pays 9.60 for 80 photos. We need to find who has the better deal, meaning who pays less per photo. 2. **Formula used:** Cost per photo = \frac{Total cost}{Number of photos} 3. **Calculate Hana's cost per photo:** $$\text{Hana's cost per photo} = \frac{16.50}{150}$$ 4. **Calculate Freya's cost per photo:** $$\text{Freya's cost per photo} = \frac{9.60}{80}$$ 5. **Simplify Hana's cost per photo:** $$\frac{16.50}{150} = \frac{\cancel{16.50}}{\cancel{150}} = 0.11$$ 6. **Simplify Freya's cost per photo:** $$\frac{9.60}{80} = \frac{\cancel{9.60}}{\cancel{80}} = 0.12$$ 7. **Compare the costs:** Hana pays 0.11 per photo, Freya pays 0.12 per photo. 8. **Conclusion:** Hana has the better deal because she pays less per photo.