1. **State the problem:** Ambaye has cows and oxes. Together, they have 512 eyes and 1024 legs. We know Ambaye has 204 oxes. We need to find how many cows he has. 2. **Define variables:** Let $c$ be the number of cows. 3. **Important facts:** - Each cow and ox has 2 eyes. - Each cow and ox has 4 legs. 4. **Use the eyes information:** Total eyes = 512 Since each animal has 2 eyes, $$2(c + 204) = 512$$ Simplify: $$c + 204 = \frac{512}{2} = 256$$ $$c = 256 - 204 = 52$$ 5. **Use the legs information to verify:** Total legs = 1024 Each animal has 4 legs, $$4(c + 204) = 1024$$ Simplify: $$c + 204 = \frac{1024}{4} = 256$$ $$c = 256 - 204 = 52$$ 6. **Conclusion:** Ambaye has **52 cows**. This matches both eyes and legs counts, confirming the answer.