1. **State the problem:** We are given the number of crimes committed in 2011 and the percentage increase from 2011 to 2012 for three places. We need to find the number of crimes committed in 2012 for each place. 2. **Formula used:** To find the 2012 value when we know the 2011 value and the percentage increase, use: $$\text{2012 crimes} = \text{2011 crimes} \times \left(1 + \frac{\text{percentage increase}}{100}\right)$$ 3. **Calculate for Brightrock Village:** $$\text{2012 crimes} = 4 \times \left(1 + \frac{25}{100}\right) = 4 \times 1.25 = 5$$ 4. **Calculate for Eastmist City:** $$\text{2012 crimes} = 3000 \times \left(1 + \frac{13}{100}\right) = 3000 \times 1.13 = 3390$$ 5. **Calculate for Westbridge Town:** $$\text{2012 crimes} = 700 \times \left(1 + \frac{10}{100}\right) = 700 \times 1.10 = 770$$ 6. **Summary:** The number of crimes committed in 2012 are: - Brightrock Village: 5 - Eastmist City: 3390 - Westbridge Town: 770 These calculations show how to apply percentage increase to find new values from old values.