1. The problem asks to find the cube root of 64, written as $\sqrt[3]{64} = ?$.
2. The cube root of a number $x$ is a value $y$ such that $y^3 = x$.
3. We want to find $y$ such that $y^3 = 64$.
4. Since $64 = 4^3$, we have $y = 4$.
5. Therefore, $\sqrt[3]{64} = 4$.
6. The answer is 4.
Cube Root 7Cd3D1
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