1. **State the problem:** Find the domain of the function $$y = \sqrt[3]{x - 1}$$. 2. **Recall the domain rule for cube root functions:** The cube root function $$\sqrt[3]{x}$$ is defined for all real numbers because cube roots of negative numbers are real. 3. **Apply the rule to the function:** Since the function is $$y = \sqrt[3]{x - 1}$$, the expression inside the cube root, $$x - 1$$, can be any real number. 4. **Write the domain:** Therefore, the domain is all real numbers, which can be written as $$-\infty < x < \infty$$. **Final answer:** The domain of $$y = \sqrt[3]{x - 1}$$ is $$-\infty < x < \infty$$.