1. The problem asks us to list at least 5 points on the graph of the cubic function $f(x) = x^3$. 2. The function $f(x) = x^3$ means for any input $x$, the output $y$ is $x$ multiplied by itself three times: $$y = x^3$$ 3. To find points on the graph, we pick values for $x$ and calculate $y$. 4. Let's choose some positive and negative values for $x$ and compute $y$: - For $x = -2$: $$y = (-2)^3 = -8$$ so the point is $(-2, -8)$. - For $x = -1$: $$y = (-1)^3 = -1$$ so the point is $(-1, -1)$. - For $x = 0$: $$y = 0^3 = 0$$ so the point is $(0, 0)$. - For $x = 1$: $$y = 1^3 = 1$$ so the point is $(1, 1)$. - For $x = 2$: $$y = 2^3 = 8$$ so the point is $(2, 8)$. 5. These points show the characteristic shape of the cubic function: it passes through the origin and increases steeply for positive $x$ and decreases steeply for negative $x$. Final answer: The points $(-2, -8)$, $(-1, -1)$, $(0, 0)$, $(1, 1)$, and $(2, 8)$ lie on the graph of $f(x) = x^3$.