Subjects algebra

Currency Conversion 1De68E

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1. **State the problem:** Byron converted some pounds (£) into euros (€) at one of two shops. We know the conversion rates from Maisy and Oliver's conversions: - Shop A: £40 = €47.20 - Shop B: £83 = €96.28 Byron received €68.44. We need to find the smallest amount of pounds Byron could have converted. 2. **Find the conversion rates:** - Shop A rate: $$\text{rate}_A = \frac{47.20}{40} = 1.18$$ euros per pound. - Shop B rate: $$\text{rate}_B = \frac{96.28}{83} \approx 1.16$$ euros per pound. 3. **Calculate pounds converted at each shop:** - At Shop A: $$\text{pounds}_A = \frac{68.44}{1.18}$$ - At Shop B: $$\text{pounds}_B = \frac{68.44}{1.16}$$ 4. **Simplify each:** - Shop A: $$\text{pounds}_A = \frac{68.44}{1.18} = \frac{68.44}{\cancel{1.18}} \approx 58.00$$ - Shop B: $$\text{pounds}_B = \frac{68.44}{1.16} = \frac{68.44}{\cancel{1.16}} \approx 59.00$$ 5. **Compare and conclude:** The smallest amount of pounds Byron could have converted is approximately £58.00 at Shop A. **Final answer:** $$\boxed{58}$$ pounds at Shop A.