1. The problem asks to determine the interval where the parabola is decreasing. 2. The parabola opens upwards and has its vertex at approximately $(3, -7)$. 3. For a parabola $y = a(x - h)^2 + k$ opening upwards, the function decreases on the interval to the left of the vertex $x = h$. 4. Since the vertex is at $x = 3$, the function is decreasing on the interval $$(-\infty, 3)$$. 5. Therefore, the function decreases for all $x$ values less than 3.