1. **State the problem:** Simplify the expression using De Morgan's Laws and describe the solution set for $$\sim(x < -2 \text{ or } x \geq 5)$$. 2. **Recall De Morgan's Laws:** - $$\sim (A \text{ or } B) = \sim A \text{ and } \sim B$$ - $$\sim (A \text{ and } B) = \sim A \text{ or } \sim B$$ 3. **Apply De Morgan's Law to the problem:** $$\sim(x < -2 \text{ or } x \geq 5) = \sim(x < -2) \text{ and } \sim(x \geq 5)$$ 4. **Simplify each negation:** - $$\sim(x < -2)$$ means $$x \geq -2$$ - $$\sim(x \geq 5)$$ means $$x < 5$$ 5. **Combine the simplified inequalities:** $$x \geq -2 \text{ and } x < 5$$ 6. **Describe the solution set:** The solution set is all real numbers $$x$$ such that $$x$$ is greater than or equal to $$-2$$ and less than $$5$$. **Final answer:** $$\boxed{-2 \leq x < 5}$$