1. **Identify the dependent and independent variables in the first practice problem:**
- Problem: The distance $t$ depends on the speed $S$.
- Explanation: The distance traveled depends on the speed, so the dependent variable is $t$.
- The speed $S$ causes the change, so the independent variable is $S$.
2. **Find the pattern and write an equation for the first pattern problem:**
- Given table:
$$\begin{array}{c|cccc}
x & 2 & 10 & 16 & 26 \\
y & 0 & 1 & 5 & ? \\\end{array}$$
- Step 1: Find the pattern in $y$ relative to $x$.
- Step 2: Calculate differences:
- From $x=2$ to $x=10$, $y$ changes from 0 to 1.
- From $x=10$ to $x=16$, $y$ changes from 1 to 5.
- Step 3: Try to find a linear relation $y = mx + b$.
- Using points $(2,0)$ and $(10,1)$:
$$m = \frac{1 - 0}{10 - 2} = \frac{1}{8}$$
$$b = y - mx = 0 - \frac{1}{8} \times 2 = -\frac{1}{4}$$
- Equation:
$$y = \frac{1}{8}x - \frac{1}{4}$$
- Step 4: Check with $(16,5)$:
$$y = \frac{1}{8} \times 16 - \frac{1}{4} = 2 - 0.25 = 1.75$$
This does not match 5, so the relation is not linear.
- Step 5: Try a quadratic or piecewise pattern or check differences in $y$:
Differences in $y$: 0 to 1 (1), 1 to 5 (4), difference increases by 3.
- Step 6: Assume $y$ depends on $x$ in a nonlinear way; since the problem is incomplete, we cannot find exact rule here.
- Step 7: For $x=26$, $y$ is unknown.
3. **Use the equation $y = 5x + 1$ to complete the table:**
- Given $x$ values: 1, 2, 3, 4, 5
- Calculate $y$ values:
1. $y = 5 \times 1 + 1 = 6$
2. $y = 5 \times 2 + 1 = 11$
3. $y = 5 \times 3 + 1 = 16$
4. $y = 5 \times 4 + 1 = 21$
5. $y = 5 \times 5 + 1 = 26$
- Completed table:
$$\begin{array}{c|ccccc}
x & 1 & 2 & 3 & 4 & 5 \\
y & 6 & 11 & 16 & 21 & 26 \\\end{array}$$
Dependent Independent 1Def4B
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