1. Stating the problem: factor $x^2-9$.
2. Use the difference of squares formula: $$a^2-b^2=(a-b)(a+b)$$
3. Rewrite $x^2-9$ as $x^2-3^2$.
4. Apply the formula: $$x^2-3^2=(x-3)(x+3)$$
5. Final answer: $$(x-3)(x+3)$$
Difference Of Squares 1C4921
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