1. Problem: factor $x^2-9$.
2. Use the difference of squares formula: $$a^2-b^2=(a-b)(a+b).$$
3. Rewrite $x^2-9$ as $x^2-3^2$.
4. Apply the formula: $$x^2-3^2=(x-3)(x+3).$$
5. So the factored form is $(x-3)(x+3)$.
Difference Of Squares 5A9Db1
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