1. **State the problem:** We need to find all points on the number line that are exactly 7 units away from point P, which is located at $-2$. 2. **Formula used:** The distance between two points $x$ and $a$ on a number line is given by the absolute value $|x - a|$. 3. **Apply the formula:** We want points $x$ such that $$|x - (-2)| = 7$$ which simplifies to $$|x + 2| = 7$$ 4. **Solve the absolute value equation:** This gives two cases: - Case 1: $x + 2 = 7$ $$x = 7 - 2 = 5$$ - Case 2: $x + 2 = -7$ $$x = -7 - 2 = -9$$ 5. **Check which points correspond to these values:** - $x = 5$ corresponds to point D. - $x = -9$ is not one of the labeled points on the number line. 6. **Final answer:** The point that is 7 units from P is point D at $5$. **Answer:** Point D