1. **State the problem:** We have a graph showing the distance Marla walked over time. We need to create a table of values from the graph, write an equation relating time and distance, and find distances for 12 minutes and 4 ½ minutes. 2. **Make a table of values:** From the graph, the points are approximately: | Time (minutes) | Distance (feet) | |----------------|-----------------| | 1 | 200 | | 2 | 400 | | 3 | 600 | | 4 | 800 | | 5 | 1000 | 3. **Write the equation:** The graph is linear, so distance $d$ is proportional to time $t$. The slope $m$ is change in distance over change in time: $$m = \frac{1000 - 0}{5 - 0} = \frac{1000}{5} = 200$$ The line passes through the origin $(0,0)$, so the equation is: $$d = 200t$$ 4. **Find distance for 12 minutes:** Substitute $t=12$: $$d = 200 \times 12 = 2400$$ So, Marla could walk 2400 feet in 12 minutes. 5. **Find distance for 4 ½ minutes:** Convert 4 ½ to decimal: $4.5$. $$d = 200 \times 4.5 = 900$$ So, Marla could walk 900 feet in 4 ½ minutes. **Final answers:** - Table of values as above. - Equation: $d = 200t$ - Distance at 12 minutes: 2400 feet - Distance at 4 ½ minutes: 900 feet