1. **State the problem:** Divide 560 among 3 people such that the second person gets twice as much as the first, and the third gets twice as much as the second. 2. **Set variables:** Let the amount the first person gets be $x$. 3. **Express other amounts:** The second person gets $2x$, and the third person gets $2 \times 2x = 4x$. 4. **Write the equation:** The total amount is the sum of all three shares: $$x + 2x + 4x = 560$$ 5. **Simplify the equation:** $$7x = 560$$ 6. **Solve for $x$:** $$x = \frac{560}{7}$$ 7. **Show cancellation:** $$x = \cancel{\frac{560}{7}} = 80$$ 8. **Find each person's share:** - First person: $x = 80$ - Second person: $2x = 160$ - Third person: $4x = 320$ 9. **Check the sum:** $$80 + 160 + 320 = 560$$ **Final answer:** The first person gets 80, the second gets 160, and the third gets 320.