1. **State the problem:** Simplify the expression $$\frac{x^5 y^{-6}}{x^{10} y^8}$$ and express it in the form $$\frac{1}{x^{?} y^{_}}$$. 2. **Recall the rule for dividing powers with the same base:** $$\frac{a^m}{a^n} = a^{m-n}$$. 3. **Apply the rule to the $x$ terms:** $$\frac{x^5}{x^{10}} = x^{5-10} = x^{-5}$$. 4. **Apply the rule to the $y$ terms:** $$\frac{y^{-6}}{y^8} = y^{-6-8} = y^{-14}$$. 5. **Combine the results:** $$\frac{x^5 y^{-6}}{x^{10} y^8} = x^{-5} y^{-14}$$. 6. **Rewrite with positive exponents in the denominator:** $$x^{-5} y^{-14} = \frac{1}{x^5 y^{14}}$$. **Final answer:** $$\frac{1}{x^5 y^{14}}$$