1. **State the problem:**
Pedro creates patterns of dominoes with dots. Each pattern has a certain number of dominoes and dots. We want to find which pattern number corresponds to a total of 124 dots.
2. **Analyze the patterns:**
- Pattern 1: dominoes are [1|6], [1|4], [1|6]. Number of dominoes = 3.
- Pattern 2: dominoes are [1|6], [2|4], [2|4], [1|6]. Number of dominoes = 4.
- Pattern 3: dominoes are [1|6], [2|4], [2|4], [2|4], [1|6]. Number of dominoes = 5.
3. **Count dots per domino:**
- [1|6] has $1+6=7$ dots.
- [1|4] has $1+4=5$ dots.
- [2|4] has $2+4=6$ dots.
4. **Dots in each pattern:**
- Pattern 1: two [1|6] dominoes and one [1|4] domino.
Total dots = $7 + 5 + 7 = 19$
- Pattern 2: two [1|6] dominoes and two [2|4] dominoes.
Total dots = $7 + 6 + 6 + 7 = 26$
- Pattern 3: two [1|6] dominoes and three [2|4] dominoes.
Total dots = $7 + 6 + 6 + 6 + 7 = 32$
5. **Generalize the pattern:**
- Number of dominoes in pattern $n$ is $n + 2$.
- Each pattern starts and ends with [1|6] dominoes (2 dominoes total).
- The middle dominoes are [2|4], and their count is $n - 1$.
6. **Formula for total dots in pattern $n$:**
$$\text{Total dots} = 2 \times 7 + (n - 1) \times 6 = 14 + 6(n - 1) = 14 + 6n - 6 = 6n + 8$$
7. **Find $n$ for total dots = 124:**
$$124 = 6n + 8$$
$$124 - 8 = 6n$$
$$116 = 6n$$
$$n = \frac{116}{6} = \frac{\cancel{116}}{\cancel{6}} = \frac{58}{3}$$
Since $n$ must be an integer pattern number, check if 124 dots is possible exactly.
8. **Check integer $n$:**
$\frac{58}{3} \approx 19.33$, not an integer.
Try $n=19$:
$$6 \times 19 + 8 = 114 + 8 = 122$$ dots.
Try $n=20$:
$$6 \times 20 + 8 = 120 + 8 = 128$$ dots.
9. **Conclusion:**
124 dots is not possible exactly with this pattern rule.
If the problem expects the closest pattern number, $n=19$ gives 122 dots, $n=20$ gives 128 dots.
**Final answer:**
The pattern number closest to 124 dots is $n=19$ with 122 dots or $n=20$ with 128 dots.
**Pattern rule:**
Total dots in pattern $n$ is given by $$6n + 8$$ where $n$ is the pattern number starting from 1.
Domino Pattern 065547
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