1. **State the problem:** We are given that the height of a door is 2.1 feet longer than its width, and the area of the door is 1675.8 square feet. We need to find the width and height of the door.
2. **Define variables:** Let the width be $w$ feet.
3. **Express height in terms of width:** Height $h = w + 2.1$
4. **Write the area formula:** Area $A = \text{width} \times \text{height} = w \times h$
5. **Substitute height into area formula:**
$$1675.8 = w(w + 2.1)$$
6. **Expand and form quadratic equation:**
$$1675.8 = w^2 + 2.1w$$
Rearranged:
$$w^2 + 2.1w - 1675.8 = 0$$
7. **Use quadratic formula:**
$$w = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$$
where $a=1$, $b=2.1$, $c=-1675.8$
Calculate discriminant:
$$\Delta = 2.1^2 - 4(1)(-1675.8) = 4.41 + 6703.2 = 6707.61$$
Calculate roots:
$$w = \frac{-2.1 \pm \sqrt{6707.61}}{2} = \frac{-2.1 \pm 81.89}{2}$$
8. **Find positive root (width must be positive):**
$$w = \frac{-2.1 + 81.89}{2} = \frac{79.79}{2} = 39.895$$
9. **Find height:**
$$h = w + 2.1 = 39.895 + 2.1 = 41.995$$
10. **Round to nearest tenth:**
Width $w \approx 39.9$ feet
Height $h \approx 42.0$ feet
**Final answer:**
The width of the door is approximately 39.9 feet and the height is approximately 42.0 feet.
Door Dimensions Bcc341
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