1. **Problem statement:** We have a situation where $d$ represents the number of days of driving, and the expression $14 - 0.6d$ is given. 2. **Part (a): What does $14 - 0.6d$ represent?** This expression represents the remaining amount of something (likely fuel, battery life, or a similar resource) after driving for $d$ days, starting from an initial amount of 14 units and decreasing by 0.6 units each day. 3. **Part (b): Write and solve an equation to find the number of days the teacher can drive without the warning light coming on.** Assuming the warning light comes on when the resource reaches zero, set the expression equal to zero: $$14 - 0.6d = 0$$ Solve for $d$: $$14 = 0.6d$$ $$d = \frac{14}{0.6}$$ Show cancellation step: $$d = \frac{14}{\cancel{0.6}} \times \frac{\cancel{1}}{1} = \frac{14}{0.6}$$ Calculate: $$d = 23.333...$$ So, the teacher can drive approximately 23.33 days before the warning light comes on. 4. **Part (c): Write and solve an inequality representing the situation. Explain the meaning.** The teacher can drive as long as the resource is positive (warning light off), so: $$14 - 0.6d > 0$$ Solve for $d$: $$14 > 0.6d$$ $$\frac{14}{0.6} > d$$ Show cancellation step: $$\frac{14}{\cancel{0.6}} > d$$ Calculate: $$23.333... > d$$ Or equivalently: $$d < 23.333...$$ **Meaning:** The teacher can drive for any number of days less than approximately 23.33 days without the warning light coming on. If $d$ reaches or exceeds this value, the warning light will turn on.