1. The problem states that a farmer collects eggs over three weeks and sells them in dozens for 28 each dozen. The total sales over three weeks amount to 120. 2. From the bar graph, week 1 has 90 eggs and week 2 has 120 eggs. We need to find the number of eggs collected in week 3. 3. First, convert the total sales amount into the total number of dozens sold: $$\text{Total dozens} = \frac{120}{28} \approx 4.2857$$ dozens. 4. Calculate the total eggs sold in three weeks: $$\text{Total eggs} = 4.2857 \times 12 = 51.4284$$ eggs. 5. This total eggs value seems inconsistent with the graph data (90 and 120 eggs in weeks 1 and 2 alone). Instead, let's interpret the problem as the farmer sells all eggs collected in three weeks, and the total sales amount is 120. 6. Calculate the total eggs collected in three weeks: $$\text{Total eggs} = \frac{120}{28} \times 12 = \frac{120 \times 12}{28} = \frac{1440}{28} = 51.4284$$ eggs, which again conflicts with the graph. 7. Since the graph shows 90 eggs in week 1 and 120 eggs in week 2, total eggs for weeks 1 and 2 are: $$90 + 120 = 210$$ eggs. 8. Let the number of eggs collected in week 3 be $x$. Total eggs collected in three weeks: $$210 + x$$. 9. The farmer sells eggs in dozens at 28 per dozen, so total sales amount is: $$28 \times \frac{210 + x}{12} = 120$$. 10. Solve for $x$: $$28 \times \frac{210 + x}{12} = 120$$ $$\frac{28}{12} (210 + x) = 120$$ $$\frac{7}{3} (210 + x) = 120$$ $$210 + x = \frac{120 \times 3}{7} = \frac{360}{7} \approx 51.4286$$ 11. This is impossible since 210 + x cannot be approximately 51.43. There must be a misunderstanding. 12. Re-examining, the total sales amount is 120, so total dozens sold: $$\frac{120}{28} \approx 4.2857$$ dozens. 13. Total eggs sold: $$4.2857 \times 12 = 51.4284$$ eggs. 14. Since weeks 1 and 2 already have 90 and 120 eggs, the total eggs collected in three weeks must be 90 + 120 + $x$. 15. The only way for total eggs sold to be 51.4284 is if the farmer only sold some eggs, not all collected. 16. Alternatively, the problem likely means the farmer sold eggs collected in week 3 only, amounting to 120 in sales. 17. Then, eggs collected in week 3: $$\frac{120}{28} \times 12 = \frac{1440}{28} = 51.4286$$ eggs, approximately 51 eggs. 18. Since eggs must be whole, round to 51 eggs. 19. Therefore, the bar for week 3 should extend to 51 eggs on the graph. Answer: 51 eggs