1. **State the problem:** The Yardley Tigers want to find the number of shirts where the cost from Kyle's Tees equals the cost from City Printing. 2. **Define variables and write equations:** Let $k$ be the number of shirts. Cost from Kyle's Tees: $$38 + 9k$$ Cost from City Printing: $$30 + 13k$$ We want to find $k$ such that: $$38 + 9k = 30 + 13k$$ 3. **Solve the equation:** Subtract 30 from both sides: $$38 + 9k - 30 = 30 + 13k - 30$$ $$8 + 9k = 13k$$ Subtract $9k$ from both sides: $$8 + \cancel{9k} - \cancel{9k} = 13k - \cancel{9k}$$ $$8 = 4k$$ Divide both sides by 4: $$\frac{8}{\cancel{4}} = \frac{4k}{\cancel{4}}$$ $$2 = k$$ 4. **Interpret the result:** The number of shirts where both options cost the same is $k = 2$. 5. **Find the cost at $k=2$:** Calculate cost: $$38 + 9 \times 2 = 38 + 18 = 56$$ So, the cost is 56 when the number of shirts is 2. **Final answer:** The cost is 56 when 2 shirts are ordered, making both options equally priced.