1. The problem asks to classify the equation $$24x + 1 = 24x + 68$$ as having one solution, no solution, or infinitely many solutions.
2. Start by subtracting $$24x$$ from both sides:
$$24x + 1 = 24x + 68$$
$$\cancel{24x} + 1 = \cancel{24x} + 68$$
which simplifies to:
$$1 = 68$$
3. Since $$1 \neq 68$$, this is a contradiction, meaning the equation has no solution.
4. Next, write examples of each type:
- One solution: $$8x + 24 = 7x + 24$$
- No solution: $$8x + 24 = 8x + 23$$
- Infinitely many solutions: $$8x + 24 = 8x + 24$$
5. Now, classify the given multiple choice equations:
- One solution: Equation A ($$8x + 24 = 7x + 24$$) because subtracting $$7x$$ leaves $$x = 0$$.
- No solution: Equation B ($$8x + 24 = 8x + 23$$) because subtracting $$8x$$ leaves $$24 = 23$$, a contradiction.
- Infinitely many solutions: Equation B ($$8x + 24 = 8x + 24$$) because both sides are identical.
Final answers:
- The original equation has no solution.
- One solution equation: $$8x + 24 = 7x + 24$$
- No solution equation: $$8x + 24 = 8x + 23$$
- Infinitely many solutions equation: $$8x + 24 = 8x + 24$$
Equation Classification 891D02
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